可以显示一,二,三,四家的牌
主要是为了训练我的牌感(记牌的能力),对有志于赌博或者桥牌事业的同志可能还有点用
编译为bd.exe,使用方法输入"bd -h"看帮助
以下是源代码(处理命令行参数的代码参考了vim):
#include
#include
#include
#include
using namespace std;
#include
#include
#include
static char program_name[]="bd";
#define THE_VERSION "0.1"
namespace info{
enum { WEST=0,NORTH=1,EAST=2,SOUTH=3,};
};
static char* deno[]={"Spade","Heart","Diamond","Cotton",};
static char card_symbol[]="23456789TJQKA";
// p - pointer to argument
// idx - index in argument
// default value
static int
get_number_arg(char* p,int def)
{
if (isdigit(*p))
{
def = atoi(p);
}
return def;
}
static void
print_help()
{
cout<<"Usage: "< cout<<"Bridge Dealer"< cout<<"Example: "< cout< cout<<" -p number of players, value ranges from 1 to 4"< cout<<" \""< cout<<" -n number of deals, default \"1\""< cout<<" -v,--version print version information and exit"< cout<<" -h,--help display this help and exit"< cout< exit(0);
}
static void
print_version()
{
cout< exit(0);
}
static void
dump_one_hand(vector::iterator ori,int sps=0)
{
vector::iterator iter=ori;
for(int i=0;i {
for(int j=0;j cout< for(;(iter!=ori+13) && (*iter)/13==i;iter++)
{
cout< }
cout< }
}
static void
dump_two_hands(vector::iterator o1, vector::iterator o2,int sps=0)
{
vector::iterator iter1=o1;
vector::iterator iter2=o2;
int j;
int cnt;
for(int i=0;i {
cout< cnt=2;
for(;(iter1!=o1+13) && (*iter1)/13==i;iter1++)
{
cout< cnt=cnt+2;
}
for(j=0;j cout< for(;(iter2!=o2+13) && (*iter2)/13==i;iter2++)
{
cout< }
cout< }
}
//error message routines---------------begin
static char* bs_errors[]=
{
"Unknown option",
#define BS_UNKNOWN_OPTION 0
"Too many arguments",
#define BS_TOO_MANY_ARGS 1
"Argument missing after",
#define BS_ARG_MISSING 2
"Garbage after option",
#define BS_GARBAGE 3
"Too many extra commands",
#define BS_EXTRA_CMD 4
"Invalid argument for",
#define BS_INVALID_ARG [1] [2] [3] 下一页
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